(N^2-n29)/(n-6)

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Solution for (N^2-n29)/(n-6) equation:


D( x )

n-6 = 0

n-6 = 0

n-6 = 0

n-6 = 0

x należy do R

x belongs to the empty set

(N^2-n^29)/(n-6) = 0

x belongs to the empty set

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